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mysql 判断是否大于0

select * from pre_common_block_item where bid = 4 and case when panduanziduan!=0 then panduanziduan

select count(*) from abc表 where a>0 and a

---逆向思维即可。不存在不为0的,就是全部为0,语句如下if not exists(select 1 from table_name where column_name0) begin select '全部为0' ; endelse if exists(select 1 from table_name where column_name0) begin select '存在不为0' ...

SELECT CASE WHEN 字段值 = 0 THEN ...... ELSE ..... END FROM 表

mysql> DELIMITER // mysql> CREATE PROCEDURE TestIfElse -> ( -> p_val INT -> ) -> BEGIN -> IF (p_val = 1) THEN -> SELECT '1' AS A; -> ELSEIF (p_val = 2) THEN -> SELECT '2' AS A; -> ELSE -> SELECT 'other' AS A; -> END IF; -> END/...

应该先算出 从开始到结束 的时间和,然后判断是否大于24 例如 22 -10 = 10 程序里面取整数或者小数 22.5-10.5 =10 22.3 - 10.2 = 10.1 个人认为是这样,祝你顺利!

写入“select * from pre_common_block_item where bid = 4 and case when panduanziduan!=0 then panduanziduan

思路:非整数就是小数了,先转为字符串,然后看看字符串中是否包含小数点. SELECT LOCATE('.', 数值) 是否等于0

用 or (或),and(且)来写 三个之中 : df 电费 fz 房租 sf 水费 两个为 0 另一个 不为 0,(可设置为大于 0) select * from table _ name where fz = 0 and sf = 0 and df > 0 or fz = 0 and df = 0 and sf > 0 or df = 0 and sf = 0 and f...

$con = mysql_connect("localhost","user","password") or die("连接失败"); mysql_select_db("database",$con); $sql = "select userid from wenzhang"; $result = mysql_query($sql); while($row = mysql_fetch_array($result)){ if($row[user...

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